The Time in Words Hackerrank Solution in c

Given the time in numerals we may convert it into words, as shown below:

At , use o' clock. For , use past, and for  use to. Note the space between the apostrophe and clock in o' clock. Write a program which prints the time in words for the input given in the format described.

Function Description

Complete the timeInWords function in the editor below. It should return a time string as described.

timeInWords has the following parameter(s):

• h: an integer representing hour of the day
• m: an integer representing minutes after the hour

Input Format

The first line contains , the hours portion The second line contains , the minutes portion

Constraints

Output Format

Print the time in words as described.

Sample Input 0

5
47

Sample Output 0

thirteen minutes to six

Sample Input 1

3
00

Sample Output 1

three o' clock

Sample Input 2

7
15

Sample Output 2

quarter past seven

#include<stdio.h>

#include<stdlib.h>

#include<string.h>

#include<assert.h>

#include<math.h>

int main()

{

    int h,m;

    scanf("%d\n %d\n",&h,&m);

    char *count[]={"one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fiveteen","sixteen","seventeen","eighteen","nineteen","twenty","twenty one","twenty two","twenty three","twenty four","twenty five","twenty six","twenty seven","twenty eight","twenty nine"};

    if(m==0)

    printf("%s o' clock",count[h-1]);

    else if(m>30)

    {

        if(m==45)

        printf("quarter to %s",count[h]);

        if(m==59)

        printf("%s minutes to %s",count[m-1],count[h]);

        else if(m!=45 && m!=59)

        printf("%s minutes to %s",count[60-m-1],count[h]);

    }

    else if(m<=30)

    {

        if(m==1)

        printf("%s minute past %s",count[m-1],count[h-1]);

        if(m==15)

        printf("quarter past %s",count[h-1]);

        if(m==30)

        printf("half past %s",count[h-1]);

        else if(m!=15 && m!=30 && m!=1)

        printf("%s minutes past %s",count[m-1],count[h-1]);

    }

    return 0;

}